Work done in increasing the size of a soap bubble from radius of $3 \mathrm{~cm}$ to $5 \mathrm{~cm}$ in millijoule is nearly (surface tension of soap solution $=0.03 \mathrm{Nm}^{-1}$ )

Question

Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{w}=8 \pi \mathrm{T}\left(\mathrm{r}_2^2-\mathrm{r}_1^2ight) \ & =8 \pi 	imes 0.03(25-9) 	imes 10^{-4} \ & =0.384 \pi 	imes 10^{-3} \mathrm{~J} \ & =0.384 \pi \mathrm{mJ} \approx 0.4 \pi \mathrm{mJ}\end{aligned}$

Work done in increasing the size of a soap bubble from radius of $3 \mathrm{~cm}$ to $5 \mathrm{~cm}$ in…

Solution