With usual notations in $\triangle A B C$ if $a^2+b^2-c^2=a b$, then measure of angle $C$ is
With usual notations in $\triangle A B C$ if $a^2+b^2-c^2=a b$, then measure of angle $C$ is
- $\frac{\pi}{4}$
- $\frac{\pi}{6}$
- $\frac{\pi}{2}$
- $\frac{\pi}{3}$
Solution
$\begin{aligned} & a^2+b^2-c^2=a b \\ & \Rightarrow \frac{a^2+b^2-c^2}{2 a b}=\frac{1}{2} \\ & \Rightarrow \cos c=\frac{1}{2} \\ & \Rightarrow c=\frac{\pi}{3}\end{aligned}$
Asked in: MHT CET 2022 (08 Aug Shift 1)
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