White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(X\). Chlorine reacts with…
White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(X\). Chlorine reacts with \(X\) in the presence of wood charcoal to form \(Y . X\) and \(Y\) are respectively
\(\mathrm{SO}_2, \mathrm{SO}_2 \mathrm{Cl}_2\)
\(\mathrm{SO}_2, \mathrm{SCl}_4\)
\(\mathrm{SO}_3, \mathrm{SO}_2 \mathrm{Cl}_2\)
\(\mathrm{SO}_3, \mathrm{SCl}_4\)
Solution
White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(\mathrm{SO}_2(X)\). Chlorine reacts with \(\mathrm{SO}_2\) in presence of wood charcoal to form \(\mathrm{SO}_2 \mathrm{Cl}_2(Y)\). The reaction can be written as:
\(\mathrm{P}_4 \text { (white) }+10 \mathrm{SO}_2 \mathrm{Cl}_2 \longrightarrow 4 \mathrm{PCl}_5+\underset{(X)}{10 \mathrm{SO}_2}\)
\(\underset{(X)}{\mathrm{SO}_2}+\mathrm{Cl}_2 \xrightarrow{\text { Wood charcoal }} \mathrm{SO}_2 \underset{(Y)}{\mathrm{Cl}_2}\)