White light consists of wavelengths range from $480 \mathrm{~nm}$ to $672 \mathrm{~nm}$. What will be the…
White light consists of wavelengths range from $480 \mathrm{~nm}$ to $672 \mathrm{~nm}$. What will be the wavelength range when white light is passed through glass of refractive index 1.6?
$420 \mathrm{~nm}-672 \mathrm{~nm}$
$300 \mathrm{~nm}-480 \mathrm{~nm}$
$300 \mathrm{~nm}-420 \mathrm{~nm}$
$300 \mathrm{~nm}-672 \mathrm{~nm}$
Solution
If wavelengths in air are $480 \mathrm{~nm}$ and $672 \mathrm{~nm}$, then wavelengths in a medium of refractive index 1.6 will be $\frac{480}{1.6}=300 \mathrm{~nm}$ and $\frac{672}{1.6}=420 \mathrm{~nm}$