While a collector to emitter voltage is constant in a transistor, the collector current changes by 8.2 mA…
While a collector to emitter voltage is constant in a transistor, the collector current changes by 8.2 mA when the emitter current changes by $8.3 \mathrm{~mA}$. The value of forward current ratio is
$82$
$83$
$8.2$
$8.3$
Solution
$\begin{aligned} & \Delta I_c=8.2 \mathrm{~mA} \\ & \qquad \Delta I_c=8.3 \mathrm{~mA} \\ & \text { Base current } \Delta I_b=\Delta I_c-\Delta I_c=8.3-8.2=0.1 \mathrm{~mA} \\ & \therefore \text { Forward current ratio }=\frac{\Delta I_c}{\Delta I_b}=\frac{8.2}{0.1}=82\end{aligned}$