Which substance serves as reducing agent in the following reaction ? $14 \mathrm{H}^{+}+\mathrm{Cr}_{2}…
$14 \mathrm{H}^{+}+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+3 \mathrm{Ni} \longrightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_{2} \mathrm{O}+3 \mathrm{Ni}^{2+}$
- $\mathrm{H}_{2} \mathrm{O}$
- $\mathrm{Ni}$
- $\mathrm{H}^{+}$
- $\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}$
Solution
N. of Ni changes from 0 to $+2$ and hence Ni acts as a reducing agent.
Asked in: JEE-TOPICTESTS-CHEMISTRY