Which pair among the following does not have the same bond order?

Question

Aicharya · Accepted Answer

We know that, For $\mathrm{O}_2^{+}$ Molecular orbital configuration of $\mathrm{O}_2^{+}$is $\sigma \mathrm{l} s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \sigma 2 p_z^2 \pi 2 p_x^2 \approx \pi 2 p_y^2 \pi^* 2 p_x^1$ Number of electrons in bonding orbital $=10$ Number of electrons in antibonding orbital $=5$ Bond order of $\mathrm{NO}_2^{+}=\frac{10-5}{2}=2.5$ For $\mathrm{NO}^{+}$ Molecular orbital configuration is $\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \pi 2 p_x^2 \pi 2 p_y^2 \sigma 2 p_z^2$ Number of electrons in bonding orbital $=10$ Number of electrons in antibonding orbital $=4$ Bond order $=\frac{10-4}{2}=3$ So, $\mathrm{O}_2^{+}$and $\mathrm{NO}^{+}$does not have same bond order.

Which pair among the following does not have the same bond order?

Solution