Which one of the followings has maximum number of atoms?

Which one of the followings has maximum number of atoms?

$1 g$ of $Mg (s)$ [Atomic mass of $Mg = 24$ ]
$1 g$ of $O_{2} (g)$ [Atomic mass of $O = 16$ ]
$1 g$ of $Li (s)$ [Atomic mass of $Li = 7$ ]
$1 g$ of $Ag (s)$ [Atomic mass of $Ag = 108$ ]

Solution

Number of atoms $= \frac{w}{molar mass} \times N_{A} \times atomicity$

Number of atoms in $1 g$ of $Li (s)$ = $\frac{1}{7} \times N_{A} \times 1$

Number of atoms $1 g$ of $Ag$ $(s)$ = $\frac{1}{108} \times N_{A} \times 1$

Number of atoms $1 g$ of $Mg (s)$ = $\frac{1}{24} \times N_{A} \times 1$

Number of atoms $1 g$ of $O_{2} (g)$ = $\frac{1}{32} \times N_{A} \times 2$

Asked in: MHT CET Full Test 11

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