Which one of the following statements is correct for the reaction?
Which one of the following statements is correct for the reaction?
Order is two but molecularity is one
Order is one but molecularity is two
Order is one but molecularity is one
Order is two but molecularity is two
Solution
For the reaction,
$\begin{aligned} & \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5(a q)+\mathrm{NaOH}(a q) \longrightarrow \\ & \mathrm{CH}_3 \mathrm{COONa}(a q)+\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}(a q)\end{aligned}$
the molecularity is two because two molecules are taking part.
Moreover, rate law for the reaction is,
rate $(r)=k\left[\mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5\right][\mathrm{NaOH}]$
$\therefore$ Order of reaction is $1+1=2$
