Which one of the following reactions will not form acetaldehyde?

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\stackrel{{\mathrm{CrO}}_3-{\mathrm{H}}_2{\mathrm{SO}}_4}{⟶}$
2. ${\mathrm{CH}}_2={\mathrm{CH}}_2+{\mathrm{O}}_2\frac{\mathrm{Pd}\left(\mathrm{II}\right)/\mathrm{Cu}\left(\mathrm{II}\right)}{{\mathrm{H}}_2\mathrm{O}}$
3. ${\mathrm{CH}}_3\mathrm{CN}\frac{ \mathrm{i}) \mathrm{DIBAL}-\mathrm{H}}{ \mathrm{ii} ){\mathrm{H}}_2\mathrm{O}}>$
4. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\frac{\mathrm{Cu}}{573 \mathrm{K}}>$

Solution

Asked in: JEE Main 2021 (25 Feb Shift 1)

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