Which one of the following properties is not shown by NO ?

Question

Aicharya · Accepted Answer

As per MOT, electronic configuration of NO is

σ 1 s^{2} < \overset{*}{σ} 1 s^{2} < σ 2 s^{2} < \overset{*}{σ} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < \overset{*}{π} 2 p_{x}^{1} = \overset{*}{π} 2 p_{y}^{0}

It is paramagnetic due to

π 2^{*} {py}^{1}

(unpaired electron)

Bond order of NO

(i . e . O_{_{2}}^{+}) = \frac{10 - 5}{2} = 2.5

Solution