Which one of the following gives a straight line for Freundlich adsorption isotherm?
Which one of the following gives a straight line for Freundlich adsorption isotherm?
$\log \frac{x}{m} v s \log p$
$\frac{x}{m} v s \frac{1}{p}$
$\log \frac{x}{m} v s \log \frac{1}{p}$
$\frac{x}{m} v s p$
Solution
Freundlich adsorption isotherm is as
$\frac{x}{m}=K p^{1 / n}$
Taking logarithms on both sides
$\log \frac{x}{m}=\log K+\frac{1}{n} \log p$
On plotting a graph between $\log x / m$ and $\log p$, a straight line will be obtained.