Which of the two ions from the list given below, have the geometry that is explained by the same…
Which of the two ions from the list given below, have the geometry that is explained by the same hybridisation of orbitals, $\mathrm{NO}_2^{-}, \mathrm{NO}_3^{-}, \mathrm{NH}_2^{-}, \mathrm{NH}_4^{+}, \mathrm{SCN}^{-}$?
$\mathrm{NH}_4^{+}$and $\mathrm{NO}_3^{-}$
$\mathrm{SCN}^{-}$and $\mathrm{NH}_2^{-}$
$\mathrm{NO}_2^{-}$and $\mathrm{NH}_2^{-}$
$\mathrm{NO}_2^{-}$and $\mathrm{NO}_3^{-}$
Solution
$\begin{array}{ll}
\mathrm{NO}_2^{-} & \rightarrow s p^2 \\
\mathrm{NO}_3^{-} & \rightarrow s p^2 \\
\mathrm{NH}_2^{+} & \rightarrow s p^3
\end{array}$
$\begin{array}{ll}
\mathrm{NH}_4^{-} & \rightarrow s p^3 \\
\mathrm{SCN}^{-} & \rightarrow s p
\end{array}$
$\therefore \quad \mathrm{NO}_2^{-}$and $\mathrm{NO}_3^{-}$both have the same hybridisation.
$\therefore\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ has minimum number of unpaired electrons and thus, minimum paramagnetic behaviour.
$\therefore\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ has minimum number of unpaired electrons and thus, minimum paramagnetic behaviour.