Which of the following statement is correct regarding \(p-V\) graph? 1. Slope of \(p-V\) graph in an…

Which of the following statement is correct regarding \(p-V\) graph? 1. Slope of \(p-V\) graph in an isothermal process is \(-\frac{p}{V}\). 2. Slope of \(p-V\) graph in an adiabatic process is \(-\frac{p}{V}\). 3. Slope of \(p-V\) graph in an isochoric process is \(-\frac{\gamma p}{V}\). 4. Slope of \(p-V\) graph in an isobaric process is zero.
  1. 1, 3, 4 are correct
  2. 2, 3 are correct
  3. 1, 4 are correct
  4. 2,3,4 are correct

Solution

(i) and (iv) options are correct. (i) Slope of \(p-V\) graph in an isothermal process is \(-\frac{p}{V}\) this is correct.
For isothermal process, slope of \(p-V^{\prime}\) curve \(\frac{d p}{d V}=-\frac{p}{V}\) (ii) Slope of \(p-V\) group in an adiabatic process is \(-\frac{p}{V}\), which is wrong.
Because slope of \(p-V\) graph in an adiabatic process is \(-\frac{\gamma p}{V}\). (iii) Slope of \(p\) - \(V\) graph in an isochoric process is \(-\frac{\gamma p}{V}\) this option is wrong. Because slope of \(p-V\) graph for isochoric process is \(\frac{d p}{-\frac{d V}{V}}-\frac{d V}{V}=\frac{d p}{0}=\infty\)
(d) Slope of \(p-V\) graph in an isobaric process is zero. This option is correct.
\(p-V\) curve is a straight line parallel to volume axis, slope of \(p\) - \(V\) curve for an isobaric process \(\frac{d p}{d V}=0.\)

Asked in: AP EAMCET 2019 (22 Apr Shift 1)

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