Which of the following represents the given mode of hybridisation $s p^{2}-s p^{2}-s p-s p$ from left to…
- $\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{C} \equiv \mathrm{N}$
- $\mathrm{HC} \equiv \mathrm{C}-\mathrm{C} \equiv \mathrm{CH}$
- $\mathrm{H}_{2} \mathrm{C}=\mathrm{C}=\mathrm{C}=\mathrm{CH}_{2}$

Solution
$\quad$$\quad$ 1$\quad$$\quad$ 2 $\quad$ 3 $\quad$ 4
$3 \sigma$ bonds $\left(s p^{2}ight.$ hybridisation);
$2 \sigma$ bonds $(s p$ -hybridisation)
$\mathrm{C}_{1}=3 \sigma$ bonds, $\mathrm{C}_{2}=3 \sigma$ bonds
$\mathrm{C}_{3}=2 \sigma$ bonds ,
Asked in: JEE-TOPICTESTS-CHEMISTRY
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