Which of the following reactions proceeds via a secondary free radical?
Which of the following reactions proceeds via a secondary free radical?
- $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2 \underset{\text { UV light }}{\stackrel{\mathrm{HBr}}{\longrightarrow}}$ $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{Br}$
- $\mathrm{C}_6 \mathrm{H}_6 \stackrel{\mathrm{Br}_2 / \mathrm{FeBr}_3}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{Br}$
- $\mathrm{C}_6 \mathrm{H}_6 \underset{\text { UV light }}{\stackrel{\mathrm{Br}_2}{\longrightarrow}} \mathrm{CH}_3-\mathrm{CH}_2 \mathrm{Br}$
Solution
$\mathrm{H}-\mathrm{Br} \stackrel{\mathrm{UV}}{\longrightarrow} \dot{\mathrm{H}}+\mathrm{Br}$.
$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{B} \dot{\mathrm{r}} \longrightarrow \mathrm{CH}_3-\mathrm{CH}-\mathrm{CH}_2 \mathrm{Br}$
$\mathrm{CH}_3 \mathrm{CH}-\mathrm{CH}_2 \mathrm{Br} \stackrel{\dot{\mathrm{H}}}{\longrightarrow} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}$
Asked in: AP EAMCET 2003
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