Which of the following orders is true regarding the basic nature of $\mathrm{NH}_{2}$ group?
- $o$-Toluidine $>$ Aniline $>o$-Nitroaniline
- $o$-Toluidine $ < $ Aniline $>o$-Nitroaniline
- $o$-Toluidine $ < $ Aniline $ < o$-Nitroaniline
- $o$-Toluidine $>$ Aniline $ < o$-Nitroaniline
Solution
The correct order of basic strength of aromatic amines is o $-$ Toluidine $ < $ Aniline $>0-$ Nitroaniline.
Aniline is more basic than ortho nitro aniline because the presence of electron withdrawing nitro group decreases the ease with which $\mathrm{N}$ can donate a lonepair of electrons.
o-Toluidine is less basic than aniline because whenever a substituent is present in the ortho position, it decreases its basicity.
Asked in: JEE-TOPICTESTS-CHEMISTRY