Which of the following molecule has bond order 2?

Question

Aicharya · Accepted Answer

The electronic configuration of $\mathrm{O}_2$ molecule is $\begin{aligned} & (\sigma 1 \mathrm{~s})^2\left(\sigma^* 1 \mathrm{~s}\right)^2(\sigma 2 \mathrm{~s})^2\left(\sigma^* 2 \mathrm{~s}\right)^2\left(\sigma 2 \mathrm{p}_{\mathrm{z}}\right)^2\left(\pi 2 \mathrm{p}_{\mathrm{x}}\right)^2 \\ & \left(\pi 2 \mathrm{p}_{\mathrm{y}}\right)^2\left(\pi^* 2 \mathrm{p}_{\mathrm{x}}\right)^1\left(\pi^* 2 \mathrm{p}_{\mathrm{y}}\right)^1 \end{aligned}$
Bond order of $\mathrm{O}_2$ molecule $=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{10-6}{2}=2$

Which of the following molecule has bond order 2?

Solution