Which of the following is the correct order of increasing field strength of ligands to form coordination…

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?
  1. $SCN^{-} < F^{-} < CN^{-} < C_{2}O_{4}^{2-}$
  2. $F^{-} < SCN^{-} < C_{2}O_{4}^{2-} < CN^{-}$
  3. $CN^{-} < C_{2}O_{4}^{2-} < SCN^{-} < F^{-}$
  4. $SCN^{-} < F^{-} < C_{2}O_{4}^{2-} < CN^{-}$

Solution

$\begin{aligned} & \mathrm{I}^{-} < \mathrm{Br}^{-} < \mathrm{S}^{2-} < \mathrm{SCN}^{-}(\mathrm{S}-\text{bonded}) < \mathrm{Cl}^{-} < \mathrm{NO}_3^{-} < \mathrm{N}_3^{-} < \mathrm{F}^{-} < \mathrm{OH}^{-} < \mathrm{C}_2 \mathrm{O}_4^{2-} < \mathrm{H}_2 \mathrm{O} < \mathrm{NCS}^{-}(\mathrm{N}-\text{bonded}) < \\ & \mathrm{CH}_3 \mathrm{CN} < \text{py (pyridine)} < \mathrm{NH}_3 < \text{en (ethylenediamine)} < \text{bipy}(2,2^{\prime} \text{-bipyridine}) < \text{phen (1,10-phenanthroline)} \\ & < \mathrm{NO}_2^{-}(\mathrm{N} \text{-bonded}) < \mathrm{PPh}_3 \text{(Triphenylphosphine)} < \mathrm{CN}^{-} < \mathrm{CO} \end{aligned}$

Asked in: NEET 2020 (Phase 1)

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