Which of the following is correct increasing order of lone pair of electrons on the central atom?
- $\mathrm{IF}_{7} < \mathrm{IF}_{5} < \mathrm{ClF}_{3} < \mathrm{XeF}_{2}$
- $\mathrm{IF}_{7} < \mathrm{XeF}_{2} < \mathrm{ClF}_{2} < \mathrm{IF}_{5}$
- $\mathrm{IF}_{7} < \mathrm{ClF}_{3} < \mathrm{XeF}_{2} < \mathrm{IF}_{5}$
- $\mathrm{IF}_{7} < \mathrm{XeF}_{2} < \mathrm{IF}_{5} < \mathrm{ClF}_{3}$
Solution
\begin{array}{cc}
Species & Number of lone pairs on central atom \\
\hline \mathrm{IF}_{7} & 0 \\
\hline \mathrm{IF}_{5} & 1 \\
\hline \mathrm{ClF}_{3} & 2 \\
\hline \mathrm{XeF}_{2} & 3 \\
\hline
\end{array}
Thus the correct increasing order is
$\mathrm{IF}_{7} < \mathrm{IF}_{5} < \mathrm{ClF}_{3} < \mathrm{XeF}_{2}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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