Which of the following is a correct statement?
- Aqueous solutions of $\mathrm{Cu}^{+}$and $\mathrm{Zn}^{2+}$ are colourless
- Aqueous solutions of $\mathrm{Cu}^{2+}$ and $\mathrm{Zn}^{2+}$ are colourless
- Aqueous solution of $\mathrm{Fe}^{3+}$ is green in colour
- Aqueous solution of $\mathrm{MnO}_4^{-}$is colourless
Solution

(No unpaired electrons, so it is colourless) $\mathrm{Zn}^{2+}=[\mathrm{Ar}] 3 d^{10}$ (No unpaired electrons, so it is colourless) (b) $\mathrm{Cu}^{2+}=[\mathrm{Ar}] 3 d^9$

(One unpaired electron is present, so it is coloured) $\mathrm{Zn}^{2+}$ is colourless. (c) The colour of $\mathrm{Fe}^{2+}$ is green while that of $\mathrm{Fe}^{3+}$ is blue. (d) $\mathrm{MnO}_4^{-}$contains no unpaired electrons, however, it is coloured due to charge transfer. Thus, only statement given in option (a) is correct.
Asked in: AP EAMCET 2010
Practice more Transition and Inner Transition Elements questions on Aicharya