Which of the following expression is correct

Gibbs free energy is related to standard Gibbs free energy according to the equation.

$\mathrm{\Delta G}=\mathrm{\Delta G}°+\mathrm{RTlnQ}$ Where Q is Reaction quotient.

As we know at equilibrium Change in Gibbs free energy will be zero. And value of $\mathrm{Q}$ will be equal to the value of equilibrium constant.

Putting these values in equation

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${\mathrm{\Delta G}}^{\mathrm{o}}=-\mathrm{RTlnK}$