Which of the following equations gives combined relationship of Boyle's law and Charle's law?

Which of the following equations gives combined relationship of Boyle's law and Charle's law?
  1. $\frac{\mathrm{P}_1 \mathrm{~V}_2}{\mathrm{~T}_1}=\frac{\mathrm{P}_2 \mathrm{~V}_1}{\mathrm{~T}_2}$
  2. $\mathrm{n}=\frac{\mathrm{RT}}{\mathrm{PV}}$
  3. $\frac{P_1 V_1}{T_1}=\frac{P_2 V_2}{T_2}$
  4. $\mathrm{p}=\frac{\mathrm{RT}}{\mathrm{nV}}$

Solution

Charles' law is the change in volume with respect to temperature at constant pressure, while Boyle's law is the change in volume with respect to pressure at a constant temperature. Taking a gas of volume $V_1$, pressure $P_1$ and temperature $T_1$, and let its change have a state $\left(V_2, P_2, T_2\right)$, then according to Boyle's law, $P_1 V_1=P_2 V_2 \ldots \ldots . . . .(1)$ Then keeping this constant pressure, move to state $\left(V_2, P_2, T_2\right)$ using Charles' law, $\frac{V_2}{T_1}=\frac{V_2}{T_2} \ldots \ldots . . . .(2)$ Solving for $V_2$, in both (1) and (2) and then equating them, we get- $\frac{P_1 V_1}{T_1}=\frac{P_2 V_2}{T_2}$ After changing the pressure, volume and temperature of the gas, still their product is equal, suggesting that the relation is constant: $\frac{P V}{T}=k$.

Asked in: MHT CET 2024 (16 May Shift 1)

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