Which of the following conversions is Hofmann Elimination reaction?

Which of the following conversions is Hofmann Elimination reaction?
  1. $\quad \mathrm{RCONH}_2 \xrightarrow{\mathrm{Br}_2, \mathrm{KOH}_{(\mathrm{aq})}} \mathrm{R}-\mathrm{NH}_2$
  2. $\quad \mathrm{R}-\mathrm{NH}_2 \xrightarrow[\text { excess }]{\mathrm{R}-\mathrm{X}} \mathrm{R}_4 \mathrm{NX}$
  3. $\quad \mathrm{R}_4 \mathrm{NX} \xrightarrow[\Delta]{\text { moist } \mathrm{Ag}_2 \mathrm{O}}$ Alkene $+\mathrm{R}_3 \mathrm{~N}$
  4. $\quad \mathrm{RCN} \xrightarrow{\mathrm{Na} / C_2 \mathrm{H}_5 \mathrm{OH}} \mathrm{RCH}_2 \mathrm{NH}_2$

Solution

The Hofmann elimination reaction is a reaction in which a primary amide (RCONH2) undergoes elimination to form an amine and an alkene. This is typically done using excess aqueous potassium hydroxide $(\mathrm{KOH})$.

Asked in: MHT CET 2024 (16 May Shift 2)

Practice more Amines questions on Aicharya