Which of the following compounds will exhibit geometrical isomerism?

1. 1, 1 - Diphenyl - 1 - propane
2. 1 - Phenyl - 2 - butene
3. 3 - Phenyl - 1 - butene
4. 2 - Phenyl - 1 - butene

Solution

To exhibit geometric isomerism, the double bonded carbon should have two different substitutents. Terminal alkene will not show geometric isomerism

Asked in: JEE Main 2015 (04 Apr)

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