Which of the following complexes formed by Nickel is tetrahedral and paramagnetic?

According to the spectrochemical series, the cyanide and carbonyl ligands are the strong field ligands and chloride is a weak field ligand. The nickel with the six ligands formed the octahedral compounds. Nickel with four ligands formed the square planar and tetrahedral compounds. The nickles with strong field ligands formed the square planar complex and tetrahedral with the weak field ligand. ${\left[\mathrm{Ni}(\mathrm{Cl}{)}_4\right]}^{2-}$ is a tetrahedral complex. It has the ${\mathrm{Ni}}^{2+}$. It has the configuration of ${\mathrm{e}}^4{{\mathrm{t}}_2}^4$. So, it has the two unpaired electrons. So, it is a paramagnetic complex.

Hence, the ${\left[\mathrm{Ni}(\mathrm{Cl}{)}_4\right]}^{2-}$ complexes formed by Nickel is tetrahedral and paramagnetic.