Which of the following circuits correctly represents the following truth table ?

Question

Aicharya · Accepted Answer

For circuit 1 $A \cdot B=\overline{Y+\bar{A}}=C$ A B $\overline{Y+\bar{A}}=C$ $\begin{array}{lllll}0 & 0 & 0 & 1 & 0 \ 0 & 1 & 0 & 1 & 0 \ 1 & 0 & 0 & 0 & 1 \ 1 & 1 & 1 & 0 & 0\end{array}$

Which of the following circuits correctly represents the following truth table ?

Solution