Which of the compounds among \(\mathrm{N}_2 \mathrm{O}, \mathrm{NO}\), \(\mathrm{N}_2 \mathrm{O}_3,…
- \(\mathrm{NO}, \mathrm{NO}_2, \mathrm{~N}_2 \mathrm{O}_3\)
- \(\mathrm{N}_2 \mathrm{O}, \mathrm{N}_2 \mathrm{O}_3, \mathrm{~N}_2 \mathrm{O}_4, \mathrm{~N}_2 \mathrm{O}_5\)
- \(\mathrm{NO}, \mathrm{NO}_2\)
- \(\mathrm{N}_2 \mathrm{O}_4, \mathrm{~N}_2 \mathrm{O}_5\)
Solution

\(\mathrm{N}_2 \mathrm{O}, \mathrm{N}_2 \mathrm{O}_3, \mathrm{~N}_2 \mathrm{O}_4, \mathrm{~N}_2 \mathrm{O}_5\) do not have unpaired electrons \((n=0)\). So, they are diamagnetic \((\mu=0)\).
Asked in: AP EAMCET 2020 (17 Sep Shift 1)
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