Which is rate constant of a first order reaction if 0.08 mole of reactant reduces to 0.02 mole in 23.03 minute?

Question

Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{K}=\frac{2.303}{\mathrm{t}} \log \frac{[\mathrm{A}]_0}{[\mathrm{~A}]_{\mathrm{t}}} \ & \mathrm{K}=\frac{2.303}{23.03} \cdot \log \frac{0.08}{0.02} \ & \mathrm{~K}=\frac{1}{10} \log 4 \ & =\frac{2 \log 2}{10}=0.0602 \mathrm{~min}^{-1}\end{aligned}$

Which is rate constant of a first order reaction if 0.08 mole of reactant reduces to 0.02 mole in 23.03…

Solution