Which is not the correct order for the stated property?
- $\mathrm{Ba}>\mathrm{Sr}>\mathrm{Mg} ;$ atomic radius
- $\mathrm{F}>\mathrm{O}>\mathrm{N}$; first ionization enthalpy
- $\mathrm{Cl}>\mathrm{F}>\mathrm{I} ;$ electron affinity
- $\mathrm{O}>\mathrm{Se}>$ Te $;$ electronegativity
Solution
$\mathrm{F}>\mathrm{O}>\mathrm{N}$
But N has half-filled structure, therefore, it is more stable than $\mathrm{O}$. That is why its ionization enthalpy is higher than $\mathrm{O}$. Thus, the correct order of IE is
$\mathrm{F}>\mathrm{N}>\mathrm{O}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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