Which among the following elements has completely filled $4 \mathrm{~d}$ orbital?
Which among the following elements has completely filled $4 \mathrm{~d}$ orbital?
- Ag
- $\mathrm{Cd}$
- $\mathrm{Sc}$
- $\mathrm{Zr}$
Solution
$\mathrm{Cd}(\mathrm{z}=48) \Rightarrow[\mathrm{Kr}] 4 \mathrm{~d}^{10} 5 \mathrm{~s}^2$
Cd has completely filled $4 \mathrm{~d}$ - orbital.
Asked in: MHT CET 2021 (20 Sep Shift 2)
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