Which among the following crystal lattices occupies all of the cubic holes by cations?

Which among the following crystal lattices occupies all of the cubic holes by cations?
  1. $\mathrm{SrCl}_{2}$
  2. $\mathrm{CaF}_{2}$
  3. $\mathrm{CsCl}$
  4. $\mathrm{UO}_{2}$

Solution

$\mathrm{CsCl}$ Cations inhabited all of the cubic holes in $\mathrm{CsCl}$ crystal lattices. A single atom in the cube's centre belongs to this unit cell, and the unit cell has only one body centre. As a result, the compound's formula is $\mathrm{CsCl}$, which stands for body-centred cubic cell. Particles are present in the corners of the cube, as well as one particle in the centre of the body, in this sort of cell.

Asked in: MHT CET 2020 (19 Oct Shift 2)

Practice more Solid State questions on Aicharya