Which among the following cations will form lowest stability complex if the ligand remains the same?
Which among the following cations will form lowest stability complex if the ligand remains the same?
$\mathrm{Cu}^{2+}$
$\mathrm{Fe}^{2+}$
$\mathrm{Cd}^{2+}$
$\mathrm{Ni}^{2+}$
Solution
The stability of metal complex increases with decrease in size of the metal cations. $\mathrm{Cd}^{2+}$ has highest size among given cations, so it will form lowest stability complex