$\int_2^5 2[x] d 18x=\{$ where $[x]$ denotes the greatest integer function $\leq x\}$

$\int_2^5 2[x] d 18x=\{$ where $[x]$ denotes the greatest integer function $\leq x\}$
  1. 18
  2. 16
  3. 12
  4. 24

Solution

$\begin{aligned} & \text { Let } I=\int_2^5 2[x] d x \\ & =\int_2^3 2(2) d x+\int_3^4 2(3) d x+\int_4^5 2(4) d x \\ & =4[x]_2^3+6[x]_3^4+8[x]_4^5=4+6+8=18\end{aligned}$

Asked in: MHT CET 2021 (24 Sep Shift 2)

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