When ' \(x\) ' \(\times 10^{-2} \mathrm{~mL}\) methanol (molar mass \(=32 \mathrm{~g}\); density \(=0.792…

When ' \(x\) ' \(\times 10^{-2} \mathrm{~mL}\) methanol (molar mass \(=32 \mathrm{~g}\); density \(=0.792 \mathrm{~g} / \mathrm{cm}^3\)) is added to \(100 \mathrm{~mL}\) water (density \(=1 \mathrm{~g} / \mathrm{cm}^3\)), the following diagram is obtained.
\(x=\) ______ (nearest integer). [Given : Molal freezing point depression constant of water at \(273.15 \mathrm{~K}\) is \(1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)]

Solution

$\begin{aligned} & \Delta \mathrm{T}_{\mathrm{f}}=273.15-270.65=2.5 \mathrm{~K} \\ & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{K}_{\mathrm{f}} \mathrm{m} \Rightarrow 2.5=1.86 \times \frac{\mathrm{n}}{0.1} \\ & \Rightarrow \mathrm{n}=0.1344 \text { moles } \\ & \Rightarrow \mathrm{w}=0.1344 \times 32=4.3 \mathrm{~g} \\ & \text { Volume }=\frac{4.3}{0.792}=5.43 \mathrm{ml}=543 \times 10^{-2} \mathrm{ml}\end{aligned}$

Asked in: JEE Main 2024 (06 Apr Shift 2)

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