When vector A → = 2 i ^ + 3 j ^ + 2 k ^ is subtracted from vector B → , it gives a vector equal…

When vector A=2i^+3j^+2k^ is subtracted from vector B, it gives a vector equal to 2j^. Then the magnitude of vector B will be:
  1. 5
  2. 3
  3. 6
  4. 33

Solution

It is given that A=2i^+3j^+2k^.

By the given condition,

 B-(2i^+3j^+2k^)=2j^

 B=2i^+5j^+2k^ 

The magnitude is given by the formula,B=B2x+B2y+B2z
 |B|=4+25+4=33           

Asked in: JEE Main 2023 (11 Apr Shift 2)

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