When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can be written as : ${…

When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can be written as : ${ }_{92} \mathrm{U}^{235}+{ }_0 n^1 \rightarrow{ }_{56} \mathrm{Ba}^{141}+{ }_{36} \mathrm{Kr}^{92}+3 x+\mathrm{Q}($ energy) where three particles named $x$ are produced and energy $\mathrm{Q}$ is released. What is the name of the particle $x$ ?
  1. electron
  2. $\alpha$-particle
  3. neutron
  4. neutrino

Solution

Nuclear fission equation $\begin{aligned} { }_{92} \mathrm{U}^{135}+{ }_0 \mathrm{n}^1 \longrightarrow & { }_{56} \mathrm{Ba}^{141}+{ }_{36} \mathrm{Kr}^{92} \\ & +3{ }_0 \mathrm{n}^1+\mathrm{Q}(\text { energy }) \end{aligned}$ Hence particle $\mathrm{x}$ is neutron.

Asked in: JEE Main 2013 (09 Apr Online)

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