When three capacitors of equal capacities are connected in parallel and one of the same capacity, capacitor…

When three capacitors of equal capacities are connected in parallel and one of the same capacity, capacitor is connected in series with the combination. The resultant capacity is $4.5 \mu \mathrm{~F}$. The capacity of each capacitor is
  1. $\quad 5 \cdot \mu \mathrm{~F}$
  2. $6 \mu \mathrm{~F}$
  3. $7 \mu \mathrm{~F}$
  4. $8 \mu \mathrm{~F}$

Solution


$\begin{aligned} & \therefore \quad C_{e q}=\frac{3 C \times C}{3 C+C}=\frac{3 C^2}{4 C} \\ & \therefore \quad C_{e q}=\frac{3 C}{4} \\ & \therefore \quad C=\frac{4 C_{e q}}{3}=\frac{4 \times 4.5}{3}=6 \mu \mathrm{~F}\end{aligned}$

Asked in: MHT CET 2024 (11 May Shift 1)

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