When these two spheres are made to touch with each other, then final charge on bigger sphere will be:

When these two spheres are made to touch with each other, then final charge on bigger sphere will be:

$0 μ C$
$12 μ C$
$4 μ C$
$8 μ C$

Solution

$8 μ C$

Final charge $= \frac{2}{1 + 2} \times (12 + 0)$

on bigger sphere $= \frac{2}{3} \times 12 = 8 μ C$

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Asked in: JEE Mains - Electrostatics - Test 1

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