When the temperature of 2 moles of an ideal gas is increased by 20 ° C at constant pressure, find the…

We know that for ideal gas

$\mathrm{PV}=\mathrm{nRT}$

Now taking small changes

$∆\left(\mathrm{PV}\right)=\mathrm{nR}∆\mathrm{T}$

as pressure remains constant. So

$\mathrm{P}∆\mathrm{V}=\mathrm{nR}∆\mathrm{T}$

Work done in increasing the kinetic energy of gas is given by

$\mathrm{W}=\mathrm{P}∆\mathrm{V}$

From the above expression, work can be modified as

$$\begin{gathered} \mathrm{W}=\mathrm{nR\Delta T} \\ \mathrm{W}=2\times \mathrm{R}\times 20 \\ \mathrm{W}=40 \mathrm{R} \end{gathered}$$