When the temperature difference between the source and sink increases, the efficiency of the heat engine
When the temperature difference between the source and sink increases, the efficiency of the heat engine
decreases
increases
is not affected
may increase or decrease
Solution
Efficiency of heat engine is given as
\(\eta=\frac{T_1-T_2}{T_1}\) ...(i)
where, \(T_1=\) temperature of source and \(\quad T_2=\) temperature of sink.
From Eq. (i), it is clear that when temperature difference between source and \(\operatorname{sink}\left(T_1-T_2\right)\) of heat engine increases, then its efficiency \(\eta\) increases.