When the switch S , in the circuit shown, is closed, then the value of current i will be:

When the switch $S,$ in the circuit shown, is closed, then the value of current $i$ will be:

1. $2 \mathrm{A}$
2. $5 \mathrm{A}$
3. $3 \mathrm{A}$
4. $4 \mathrm{A}$

Solution

$i=i_2+i_2$

$\frac{V-0}{2}=\frac{20-V}{2}+\frac{10-V}{4}$

$2V+V-10+2(V-20)=0$

$5V-50=0$

$V=10 \mathrm{V}$

$i=\frac{10}{2}=5 \mathrm{A}$

Asked in: JEE Main 2019 (09 Jan Shift 1)

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