When the mass and speed of the body are doubled, the kinetic energy of the body
When the mass and speed of the body are doubled, the kinetic energy of the body
becomes double
becomes four times
becomes eight times
remains unchanged
Solution
Given that, the mass and speed of body are doubled.
Then, final kinetic energy,
$
\mathrm{KE}_f=\frac{1}{2}(2 m)(2 v)^2=\left(\frac{1}{2} m v^2\right) 8
$
where, $m$ and $v$ are initial mass and speed.
Here, initial kinetic energy, $\mathrm{KE}_i=\frac{1}{2} m v^2$
$
\therefore \quad \mathrm{KE}_f=8 \mathrm{KE}_i
$