When the engine is switched off a vehicle of mass $M$ is moving on a rough horizontal road with momentum $p$…
When the engine is switched off a vehicle of mass $M$ is moving on a rough horizontal road with momentum $p$. If the coefficient of friction between the road and tyres of the vehicle is $\mu_k$, the distance travelled by the vehicle before it comes to rest is
$\frac{p^2}{2 \mu_k M^2 g}$
$\frac{2 \mu_k M^2 g}{p^2}$
$\frac{p^2}{2 \mu_k g}$
$\frac{p^2 M^2}{2 \mu_k g}$
Solution
We have,
$\mu_k m g s=\frac{p^2}{2 M}$
or
$s=\frac{p^2}{2 M^2 \mu_k g}$