When the electron orbiting in hydrogen atom in its ground state moves to the third excited state, the…
When the electron orbiting in hydrogen atom in its ground state moves to the third excited state, the de-Broglie wavelength associated with it
becomes zero.
remains unchanged.
will decrease.
will increase.
Solution
As $\mathrm{v} \propto \frac{1}{\mathrm{n}}$, we can also write
$\therefore \quad m v \propto \frac{1}{n} \quad \Rightarrow p \propto \frac{1}{n}$ Also,
$\lambda=\frac{\mathrm{h}}{\mathrm{p}} \quad \Rightarrow \lambda \propto \mathrm{n}$
$\therefore \quad$ Wavelength will increase.