When the current through an inductor is changed at from $2 \mathrm{~A}$ to $6 \mathrm{~A}$ in time $2…
When the current through an inductor is changed at from $2 \mathrm{~A}$ to $6 \mathrm{~A}$ in time $2 \mathrm{~s}$, emf induced in it is $3 \mathrm{~V}$. Then the inductance of the inductor is
$1.4 \mathrm{H}$
$0.8 \mathrm{H}$
$1.5 \mathrm{H}$
$0.6 \mathrm{H}$
Solution
Inductance of the inductor is given as
$\begin{aligned} & \mathrm{L}=-\frac{\varepsilon}{\frac{\mathrm{di}}{\mathrm{dt}}} \\ & =\frac{3}{\frac{6-2}{2}}=\frac{3 \times 2}{4}=1.5 \mathrm{H}\end{aligned}$