When the battery across the plates of a charged condenser is disconnected and a dielectric slab is…

When the battery across the plates of a charged condenser is disconnected and a dielectric slab is introduced between its plates then the energy stored
  1. becomes infinity
  2. does not change
  3. increases
  4. decreases

Solution

Since the battery is disconnected, the charge on the capacitor remains constant. When the dielectric slab is introduced, the capacitance increases $\mathrm{k}$ times. Energy stored, $\mathrm{U}_{\mathrm{i}}=\frac{\mathrm{q}^2}{2 \mathrm{C}}$ $\mathrm{U}_{\mathrm{f}}=\frac{\mathrm{q}^2}{2 \mathrm{kC}} < \mathrm{U}_{\mathrm{i}}$

Asked in: MHT CET 2021 (22 Sep Shift 1)

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