When tension 'T' is applied to a sonometer wire of length $\ell^{\prime}$, it vibrates with the fundamental frequency 'n'. Keeping the experimental setup same, when the tension is increased by 8 newton, the fundamental frequency becomes three times the earlier fundamental frequency (n). The…

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When tension 'T' is applied to a sonometer wire of length $\ell^{\prime}$, it vibrates with the fundamental frequency 'n'. Keeping the experimental setup same, when the tension is increased by 8 newton, the fundamental frequency becomes three times the earlier fundamental frequency (n). The initial tension applied to the wire in newton, was

Aicharya · Accepted Answer

$\mathrm{n}=\frac{1}{2 \ell} \sqrt{\frac{\mathrm{T}}{\mathrm{m}}}$ $3 \mathrm{n}=\frac{1}{2 \ell} \sqrt{\frac{\mathrm{T}+8}{\mathrm{~m}}}$ $	herefore \frac{\mathrm{n}}{3 \mathrm{n}}=\sqrt{\frac{\mathrm{T}}{\mathrm{T}+8}}$ $\frac{\mathrm{n}^{2}}{9 \mathrm{n}^{2}}=\frac{\mathrm{T}}{\mathrm{T}+8}$ $	herefore \mathrm{T}+8=9 \mathrm{~T} \Rightarrow 8 \mathrm{~T}=8 \mathrm{~N}$ $	herefore 1 \mathrm{~N}$

When tension 'T' is applied to a sonometer wire of length $\ell^{\prime}$, it vibrates with the fundamental…

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