When sulphur is boiled with $\mathrm{Na}_{2} \mathrm{SO}_{3}$ solution, the compound formed is
- Sodium sulphide
- Sodium sulphate
- Sodium persulphate
- Sodium thiosulphate
Solution
$8 \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3}+\mathrm{S} ightarrow 8 \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3}$
Hence, option (d) is correct. *
Asked in: JEE-TOPICTESTS-CHEMISTRY
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