When $200 \mathrm{~mL}$ solution of $\mathrm{HCl}$ of $\mathrm{pH}=2$ is mixed with $300 \mathrm{~mL}$…
When $200 \mathrm{~mL}$ solution of $\mathrm{HCl}$ of $\mathrm{pH}=2$ is mixed with $300 \mathrm{~mL}$ solution of $\mathrm{NaOH}$ of $\mathrm{pH}=12$, the $\mathrm{pH}$ of resulting solution is $(\log 2=0.3)$